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I understand your "conditional probability" explanation but I do not see the next game or the one after that or the one after that as dependent on the preceding one. If the next game there's an 80% chance of the Pas winning ,then THAT is where it starts and ends. The next game is a totally different island universe unto itself. One can deem an 80% chance of winning, 70, 60, 95, 100% THAT game given an entirely different set of variables that apply to THAT specific game. For example,if, as you put forth, that the 4th game is a 41% probability without any question, then you are assuming that the loss of a starting QB, WR's, D linemen or corners play no part in that specific probability..doesn't pass the "make sense" test.
Yeah, I think there is a statistical formula to determine the odds of winning all four games, but I think you need to use a weighed average and standard deviation to determine it. It isn't as simple as the flipping coin argument because we are not talking about doing the same exact event multiple times. It is four unique events with different variables.
It has been a long time since I took stats, but I don't think it is a simple conditional probability formula to figure it out.
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