Fencer
Pro Bowl Player
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OK. Let's get this worked out in one EASILY accessible place, links to which can perhaps be placed in other forums as need be.
Gay-Lussac's law says pressure is proportional to temperature. Presumably it assumes constant volume, but that's very close to being the case.
I imagine this is the total pressure, while the 12.5 figure is the relative pressure -- i.e., the relevant pressure figure is 12.5 PSI + 14.5 PSI = 27 PSI, give or take rounding, in that 14.5 PSI is a reasonable figure for sea level atmospheric pressure.
The temperatures in question are all a little below 300 Kelvin (which is 80 Farenheit or so). 5 degrees Farenheit is a little below 3 degrees Kelvin (actually, it's 25/27 * 3 degrees). So 5 degrees Farenheit should induce a little more than 25/27 * 1% change in that 27 PSI. I.e., a change of 5 degrees Farenheit equates to a change of about .25 PSI.
How am I doing?
Gay-Lussac's law says pressure is proportional to temperature. Presumably it assumes constant volume, but that's very close to being the case.
I imagine this is the total pressure, while the 12.5 figure is the relative pressure -- i.e., the relevant pressure figure is 12.5 PSI + 14.5 PSI = 27 PSI, give or take rounding, in that 14.5 PSI is a reasonable figure for sea level atmospheric pressure.
The temperatures in question are all a little below 300 Kelvin (which is 80 Farenheit or so). 5 degrees Farenheit is a little below 3 degrees Kelvin (actually, it's 25/27 * 3 degrees). So 5 degrees Farenheit should induce a little more than 25/27 * 1% change in that 27 PSI. I.e., a change of 5 degrees Farenheit equates to a change of about .25 PSI.
How am I doing?
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