Why is San Diego involved in tiebreakers?

[bobgeorge]

The official NFL playoff scenario has San Diego involved in two tiebreaker scenarios, even though they are eliminated from playoff contention.

One of the ways the Steelers can clinch a playoff berth is for San Diego to beat Denver. It says also that for KC to clinch a playoff berth, it needs to win, it needs PIT to lose and it needs SD to lose.

Why? If PIT loses and KC and SD both win, it sets up a three-way tie between the three clubs at 10-6. In a three-or-more-way tie for a wild card, the tiebreaker policy says first of all to eliminate all but the top ranked teams in each division, then apply the two-team method. In this scenario, KC knocks out SD due to better conference record. Then you apply the two-team method to KC and PIT and again KC wins on better conference record.

Am I missing something? SD is eliminated and KC wins tiebreakers with both SD and PIT.

Bob G

 

[bobgeorge]

Never mind, I just found the answer...I keep forgetting that common games is ahead of conference record. I guess that in that scenario, SD beats KC but loses to PIT. This is why a SD win knocks out KC. What KC has to hope for is to finish only in a 2-way tie with PIT and not a 3-way tie with PIT and SD.

Ye Gods.

Bob G

 

[Johnny Mac]

Yeah,

Head-to-Head -> Division -> Common Opponents -> Conference

etc.

 

[spacecrime]

The official NFL playoff scenario has San Diego involved in two tiebreaker scenarios, even though they are eliminated from playoff contention.

One of the ways the Steelers can clinch a playoff berth is for San Diego to beat Denver. It says also that for KC to clinch a playoff berth, it needs to win, it needs PIT to lose and it needs SD to lose.

Why? If PIT loses and KC and SD both win, it sets up a three-way tie between the three clubs at 10-6. In a three-or-more-way tie for a wild card, the tiebreaker policy says first of all to eliminate all but the top ranked teams in each division, then apply the two-team method. In this scenario, KC knocks out SD due to better conference record. Then you apply the two-team method to KC and PIT and again KC wins on better conference record.

Am I missing something? SD is eliminated and KC wins tiebreakers with both SD and PIT.

Bob G

• The Steelers can clinch a playoff spot with:
1. A win
2. A Chiefs loss or tie
3. A Chargers win (note: although Chargers have been eliminated, if they win vs. Broncos and they, the Chiefs and the Steelers all finish at 10-6, you would break division ties first. Chargers would win tiebreaker vs. Chiefs based on common opponents [8-4 vs 7-5] and that would eliminate the Chiefs. They would then go to tiebreaker vs. Steelers, which Pittsburgh would win based on its head-to-head win vs. Chargers).

http://sports.espn.go.com/nfl/news/story?id=2232165

 

[jczxohn1]

Never mind, I just found the answer...I keep forgetting that common games is ahead of conference record. I guess that in that scenario, SD beats KC but loses to PIT. This is why a SD win knocks out KC. What KC has to hope for is to finish only in a 2-way tie with PIT and not a 3-way tie with PIT and SD.

Ye Gods.

Bob G

Maybe this is why we will never have play-offs at the college level. PHD thesis in exercise sscience, anyone?

 

[spacecrime]

Maybe this is why we will never have play-offs at the college level. PHD thesis in exercise sscience, anyone?

The tie breaking rules are very simple and easy to understand and are only a page or so long. The key to understanding is to read them.

 

[jczxohn1]

The tie breaking rules are very simple and easy to understand and are only a page or so long. The key to understanding is to read them.

The pros have 2 conferences. Imagine transfering that to the multitude of conferences in college ball.

 

[wistahpatsfan]

The pros have 2 conferences. Imagine transfering that to the multitude of conferences in college ball.

BRILLIANT !