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Look at the point differentials in the AFC East

Discussion in 'PatsFans.com - Patriots Fan Forum' started by Fixit, Sep 20, 2007.

  1. Fixit

    Fixit In the Starting Line-Up

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    Pats: +48
    Jets: -31
    Bills: -24
    Phins: -20

    Nothing more really needs to be said.
     
  2. ddell1

    ddell1 Practice Squad Player

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    Ya I am not upset that we are up by 4 games in the division
     
  3. Oswlek

    Oswlek In the Starting Line-Up

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    What is amazing is that this is after just two weeks! So all three other teams are averaging losses by double digits.
     
  4. emoney_33

    emoney_33 Experienced Starter w/First Big Contract

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    2 games..., where you get 4?
     
  5. BadMoFo

    BadMoFo Experienced Starter w/First Big Contract

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    He can't count. :D
     
  6. ddell1

    ddell1 Practice Squad Player

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    Pats are 2-0. the Rest of the division is 0-2. For the division race we basically have a 4 game lead. Math says if you count backward from positive 2 to negative 2 you get....anyone....4
     
  7. sarge

    sarge Rotational Player and Threatening Starter's Job

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    I really hope you are joking.
     
  8. BadMoFo

    BadMoFo Experienced Starter w/First Big Contract

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    2+2=4. He's right. :D
     
  9. ddell1

    ddell1 Practice Squad Player

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    Ya well I had to try to come up with something clever after my first post. Guess nobody bought the jedi mind trick. Oh well I thought it was worth a try. lol
     
  10. BadMoFo

    BadMoFo Experienced Starter w/First Big Contract

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    Tell the truth, you weren't joking. It's OK, we won't tell no one. ;)
     
  11. emoney_33

    emoney_33 Experienced Starter w/First Big Contract

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    4 * 0.5 = 2
     
  12. ddell1

    ddell1 Practice Squad Player

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    Ya your right. It was my understanding there would be no math today. My theory sounded good to me. I will stick to my strong suits like poor spelling from now on.
     
  13. emoney_33

    emoney_33 Experienced Starter w/First Big Contract

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    let a = b

    Multiply both sides by a
    a² = ab

    Add (a² - 2ab) to both sides
    a² + a² - 2ab = ab + a² - 2ab

    Factor the left, and collect like terms on the right
    2(a² - ab) = a² - ab

    Divide both sides by (a² - ab)
    2 = 1



    I WIN
     
    Last edited: Sep 20, 2007
  14. He Ban Me

    He Ban Me Banned

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    The East sucks?
     
  15. He Ban Me

    He Ban Me Banned

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    Absolutely, 2 x 2 = 4. He's correct.
     
  16. BB_dynasty

    BB_dynasty On the Game Day Roster

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    sorry if i am wrong, but you cannot divide by a variable, because if the variable were zero, it would be undefined. that is just my understanding, not sure if it is right.
     
  17. ddell1

    ddell1 Practice Squad Player

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    Oh Christ, not more math!
     
  18. jman924

    jman924 Rotational Player and Threatening Starter's Job

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    How 'bout some content? Posting the same tired picture in every thread you troll is getting old.

    Freaking loser.:rolleyes:
     
    Last edited: Sep 20, 2007
  19. tombonneau

    tombonneau In the Starting Line-Up

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    This is pretty interesting. Of course, given your premise of a=b and a squared=ab then asquared - ab must equal 0, thus your final equation must be 0=0.

    I'm sure you already knew that though and it doesn't take away from the novelty of it. :)
     
  20. emoney_33

    emoney_33 Experienced Starter w/First Big Contract

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    Well you can divide by a variable when you know or can assume it is non-zero.

    In the above when "Divide both sides by (a² - ab)", that's illegal since a = b, we know (a² - ab) = 0. So yea the proof falls apart there but I still like to pretend 2=1 :)
     

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